2y^2-3y-104=0

Solution for 2y^2-3y-104=0 equation:

2y^2-3y-104=0

a = 2; b = -3; c = -104;
Δ = b2-4ac
Δ = -32-4·2·(-104)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-29}{2*2}=\frac{-26}{4}
=-6+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+29}{2*2}=\frac{32}{4}
=8
$